1ï¼ååæ±å¯¼æ°å¾ -1/[2â(1-x)] ï¼åæ¯æ±å¯¼æ°å¾ 2x+1 ï¼
å°x=-2代å
¥ï¼å¯æ±å¾æé为 â3/18 ã
2ï¼å½æ°å®ä¹å为 R ã
æ±å¯¼å¾ f '(x)=(1+x^2-2x^2)/(1+x^2)^2=(1-x^2)/(1+x^2)^2 ï¼
令 f '(x)=0 ï¼å¾ x1=-1 ï¼x2=1 ã
å表å¾
x ï¼-âï¼-1ï¼ -1 ï¼-1ï¼1ï¼ 1 ï¼1ï¼+âï¼
f '(x) - 0 + 0 -
f(x) å æå° å¢ æ大 å
æ以ï¼å½æ°å¨ï¼-âï¼-1ï¼ä¸ä¸ºåå½æ°ï¼å¨ï¼-1ï¼1ï¼ä¸ä¸ºå¢å½æ°ï¼å¨ï¼1ï¼+âï¼ä¸ä¸ºåå½æ°ï¼
å¨x=-1å¤ï¼å½æ°åæå°å¼ f(-1)=-1/2 ï¼å¨x=1 å¤ï¼å½æ°åæå¤§å¼ f(1)=1/2 ã
温馨提示:答案为网友推荐,仅供参考