1、解:设大钢珠有X颗,那么小钢珠有(30-X)颗
11X+7(30-X)=266
11X+210-7X=266
4X=266-210
X=56÷4
X=14
那么,小钢珠有:30-14=16颗
2、解:设大船租了X条,那么小船租了(8-X)条
6X+4(8-X)=38
6X+32-4X=38
2X=38-32
X=6÷2
X=3
那么,小船租了:8-3=5条
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追答解:设投进了X个3分球。
3X+2(9-X)=21
3X+18-2X=21
X+18=21
X=21-18
X=3