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æ£æï¼ O2 + 4e- + 2H2O=4OH- E0ï¼O2/OH-ï¼=0.401v
100kPa 1mol/L
è´æ: 2H2O +4e- = 2H2â + 4OH- E0ï¼H2O/H2ï¼=?
100kPa 1mol/L
è´æçæ¬è´¨
2H+ + 2e- = H2â E0ï¼H+/H2ï¼=0 v
Kw 100Kpa
å æ¤:
E0ï¼H2O/H2ï¼
= Eï¼H+/H2ï¼
=E0ï¼H+/H2ï¼+0.0592v /2 *lg{ ([H+]/c0)^2 /[p(H2)/p0]}
=0v +0.0592v /2 *lg[10^-14]^2
=-0.8288v
æ åçµå¨å¿
= E0ï¼O2/OH-ï¼-E0ï¼H2O/H2ï¼
=0.401v-(-0.8288v)
=1.23V
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追ç1mol/L KOH溶液ä¸[H+]=10^-14
lg{ ([H+]/c0)^2 /[p(H2)/p0]}
c0:æ åæµåº¦=1mol/L
P0æ ååå=100KPa
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