在三角形ABC中,内角A,B,C的对边分别是a,b,c已知C=2,C=π/3,若sinB=2...答:因C=π/3,所以 A+B=2π/3, A=2π/3-B sinB=2SinA=2Sin(2π/3-B)=2(sin(2π/3)cosB-cos(2π/3)sinB)=根号3*cosB+sinB 根号3*cosB=0, cosB=0, 得B=π/2,从而A=π/6, 知三角形ABC为直角三角形。由正弦定理 c/sinC=a/sinA=b/sinb, 即2/sin(π/3)=a/sin(π/6)...