已知sinα=3/5,α∈(π/2,π),求cos(α+π/3)的值

如题所述

sinα=3/5,α∈(π/2,π)
则cosα=-4/5cos(π/3+α)
=cosπ/3*cosα-sinπ/3sinα
=1/2*(-4/5)-√3/2*3/5
=-2/5-3√3/10
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第1个回答  2013-04-08
sinα=3/5,α∈(π/2,π)
则cosα=-4/5
cos(π/3+α)
=cosπ/3*cosα-sinπ/3*sinα
=1/2*(-4/5)-√3/2*3/5
=-2/5-3√3/10